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Fix Ctrl+grave being sent without Ctrl due to --clearmodifiers

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--clearmodifiers releases ALL modifiers including Ctrl, so xdotool
sends bare grave (types 'v'). Instead, explicitly release only Alt
before sending Ctrl+grave so OpenWhispr receives the correct combo.

https://claude.ai/code/session_01XKYC1basxdwtHy71tky7xm
This commit is contained in:
Claude
2026-03-25 20:37:05 +00:00
parent 9137bd2d80
commit 6991fdbbee
1 changed files with 9 additions and 3 deletions
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openwhispr-ptt.py
+9 -3
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@@ -38,12 +38,18 @@ is_recording = False
def send_whispr_toggle(): def send_whispr_toggle():
"""Send Ctrl+` to OpenWhispr via xdotool. """Send Ctrl+` to OpenWhispr via xdotool.
Uses --clearmodifiers to release any physically held keys first, We first release Alt (which we're physically holding), send Ctrl+grave,
so the simulated Ctrl+` isn't mangled into Ctrl+Alt+`. then re-press Alt. This way OpenWhispr sees clean Ctrl+` without
the Alt modifier corrupting it.
""" """
try: try:
subprocess.run( subprocess.run(
["xdotool", "key", "--clearmodifiers", WHISPR_HOTKEY], ["xdotool", "keyup", "alt"],
timeout=2,
capture_output=True,
)
subprocess.run(
["xdotool", "key", WHISPR_HOTKEY],
timeout=2, timeout=2,
capture_output=True, capture_output=True,
) )